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10x^2+67x-21=0
a = 10; b = 67; c = -21;
Δ = b2-4ac
Δ = 672-4·10·(-21)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-73}{2*10}=\frac{-140}{20} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+73}{2*10}=\frac{6}{20} =3/10 $
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